Respuesta :
The equation in slope-intercept form for the line given (-3,12) and (15,0) is
[tex]y=-\frac{2}{3}x+ 10[/tex]
Given,
The points = (-3,12) and (15,0)
We know,
Slope of the equation m= [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
Substitute the values and find the value of m
m= [tex]\frac{0-12}{15--3}[/tex]
m=[tex]-\frac{12}{18}=-\frac{2}{3}[/tex]
Slope intercept form of the equation is y= mx + b
where b is y intercept form.
Consider one point and substitute the values.
[tex]0=-\frac{2}{3}(15)+b \\0=-10+b\\b=10[/tex]
Then the slope intercept form is
[tex]y=-\frac{2}{3}x+ 10[/tex]
Hence, The equation in slope-intercept form for the line given (-3,12) and (15,0) is [tex]y=-\frac{2}{3}x+ 10[/tex]
Learn more about slope intercept form here
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