The equation in point-slope form of the line having the given slope that contain the given point m=[tex]-\frac{3}{4}[/tex] and (8,-1) is [tex]y+1=-\frac{3}{4}(x-8)[/tex]
Given,
m = [tex]\frac{-3}{4}[/tex]
The point = (8,-1)
The point-slope form of the line
[tex](y-y_{1} )=m(x-x_{1})[/tex]
Substitute the values in the equation
[tex](y-(-1))=-\frac{3}{4}(x-8)\\ y+1=-\frac{3}{4}(x-8)[/tex]
Hence, the equation in point-slope form of the line having the given slope that contain the given point m=[tex]-\frac{3}{4}[/tex] and (8,-1) is [tex]y+1=-\frac{3}{4}(x-8)[/tex]
Learn more about point slope form here
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