According to the question, to calculate the probability of the event which states that tossing a coin to get either head or tail
The total number of a coin is [tex]1[/tex]
And total number of possibilities are {H,T}
Therefore, the total number of favorable outcomes in which either head or tail can come: [tex]1[/tex]
As per question, the probability can be written as:
P(h or t) = P(h) + P(t)
[tex]= \frac{1}{2} +\frac{1}{2} =1 = 100%[/tex]
Hence, the probability of getting either head or tail is [tex]1[/tex].
The given event is mutually exclusive because it has [tex]100[/tex] percent which is close to tenth of a percent. And these two events cannot happen at the same time also, so they are mutually exclusive.
What are mutually exclusive events?
Mutually exclusive events are those events which cannot happen at the same time. For instance, in any event nobody can run forward or backward together at the same time.
To learn more about the mutually exclusive from the given link:
https://brainly.com/question/27588497
#SPJ4
