Respuesta :
According to the given data young's modulus for this material = 5.73 *(10^8 ) pa
What exactly is Young's modulus?
Young's modulus (E) of material seems to be the ratio of compressive loading () to tensile strain (). Where stress is defined as the amount of normal force per unit area ( = F/A) and strain is defined as extension per unit length ( = dl/l).
According to the given data:
Youngs modulus Y of a material is given Y = FL/ADL
where
A = area
DL = change of length
L = original length
F = force
so here we apply
Y = 65*9.8* 45/(3.14* 3.5*3.5* 10^-6 * 1.3)
Y = 5.73 *(10^8 ) pa
According to the given data young's modulus for this material = 5.73 *(10^8 ) pa
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I understand that the question you are looking for is:
A nylon rope used by mountaineers elongates 1.30 m under the weight of a 65.0-kg climber. If the rope is 45.0 m in length and 7.0 mm in diameter, what is Young's modulus for this material?
