The fundamental frequency is 102.06 Hz m/s.
We need to know about the fundamental resonant frequency to solve this problem. When the string is vibrating at its lowest resonant frequency, it should follow the rule
λ = 2L
where λ is wavelength and L is the length of string
The transverse waves on a string also can be defined as
v = √(F . l/m)
where v is velocity, F is string tension, l is the length of string and m is mass
From the question above, we know that
l = 60 cm = 0.6 m
m = 8 g = 8 x 10¯³ kg
F = 200 N
By substituting the following equation, we can calculate the wavelength
λ = 2L
λ = 2 . 0.6
λ = 1.2 m
Find the speed of the wave
v = √(F . l/m)
v = √(200 . 0.6/(8 x 10¯³))
v = 122.47 m/s
Find the frequency
v = λ . f
122.47 = 1.2 . f
f = 102.06 Hz
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