Respuesta :
The conductance of the blood vessel is 4.91× 10-6 ohm⁻
Given, here the length of blood vessel, L = 10cm.and the diameter, D = 1mm or 0.1 cm
Then, radius is equals to 0.1/2 = 0.05cm
Now, we calculate cross sectional area, which equals to πr2
A=πr² = π(0.05)²
We know that , the resistivity of blood ties between 80 ohm cm to 240ohm cm.
Therefore, The average resistivity, ρ= 80+240/2ohm cm = 160ohm cm.
Now, we calculate the resistance of the blood by the formula,
R= ρ l/A
R= 160ohm cm × 10cm/ π × (0.05) 2
R= 1600/ 7.854× 103cm2
R= 203.72× 103 ohm.
Now, we caclulate conductance and we know that it is reciprocal of resistance.
So, The conductance is, G= 1/R
G= 1/203.72× 103 ohm.
G= 4.91× 10-6 ohm⁻
Any conductor, including a lightbulb, will block the flow of an electric current; this obstruction is known as electrical resistance and is represented by the letter R. Conductors emit heat when current flows through them because all materials have an electrical resistance.
Conductance is defines as the reciprocal of the electrical resistance . It is denoted by G and it’s unit is ohm- (ohm minus).
To learn more about resistance, refer this link
https://brainly.com/question/4289257
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