282.84m/s is the speed if the tension is halved.
The wave depends on the following:-
The formula we will use is:-
[tex]$v=\sqrt{\frac{T}{p}}$[/tex]
According to the question, the speed of the tension is as follows
Where v Is the speed of the wave, T is the tension In the wire, and [tex]$\rho$[/tex] Is the density of the wire.
when tension is doubled.
[tex]&\mathbf{T}=\mathbf{2} \mathbf{T}_0 \\[/tex]
[tex]$v=\sqrt{\hat{a} \frac{2 T_{\hat{\theta}}}{I}}$[/tex]
[tex]$v=\sqrt{2} \frac{T \hat{a}}{I}$[/tex]
[tex]$v=\frac{2}{\text { vô }}$[/tex]
After calculating, the value of v get,
[tex]$v=\sqrt{2} * 200$[/tex]
The value [tex]$\mathrm{v}=282.84 \mathrm{~m} / \mathrm{s}$[/tex].
The correct question is,
The wave speed on a string under tension is 200 m/s. What is the speed if the tension is doubled?
To learn more about speed refer to:
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