Respuesta :
An isosceles triangle is one with two equal-length sides. ΔABC is an isosceles triangle.
What is the distance between two points ( p,q) and (x,y)?
The shortest distance (length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:
D = √[(x-p)² + (y-q)²] units.
Given that the coordinates of the vertices of the triangle are A(0,0), B(a, b), and C(2a, 0). Now, to prove that the given triangle is an isosceles triangle we need to find the length of each side of the triangle.
AB = √[(x₂-x₁)² + (y₂-y₁)²]
= √[(a - 0)² + (b - 0)²]
= √(a² + b²)
BC = √[(x₂-x₁)² + (y₂-y₁)²]
= √[(2a - a)² + (0 - b)²]
= √(a² + b²)
AC = √[(x₂-x₁)² + (y₂-y₁)²]
= √[(2a - 0)² + (0 - 0)²]
= √4a²
= 2a
Since the length AB and BC are the same, while the length of AC is different, therefore, ΔABC is an isosceles triangle.
Learn more about the distance between two points here:
brainly.com/question/16410393
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