Answer:
a=−2 and b=−2
Step-by-step explanation:
Let's solve your system by substitution.
7a−12b=10;−2a−4b=12
Step: Solve7a−12b=10for a:
7a−12b=10
7a−12b+12b=10+12b(Add 12b to both sides)
7a=12b+10
7a/7=12b+10/7
(Divide both sides by 7)
[tex] \sf \: a = \frac{12}{7} b + \frac{10}{7} [/tex]
Step: Substitute: 12/7b+10/7 for a in−2a−4b=12:
−2a−4b=12
−2(12/7b+10/7)−4b=12
−52/7b + −20/7=12(Simplify both sides of the equation)
−52/7b+−20/7+20/7=12+20/7
(Add 20/7 to both sides)
−52/7b=104/7
[tex] \sf \: \frac{ \frac{ - 52}{7}b }{ \frac{ - 52}{7} } = \frac{ \frac{104}{7} }{ \frac{ - 52}{7} } [/tex]
(Divide both sides by (-52)/7)
b=−2
Step: Substitute −2 for b in a =12/7b+10/7:
a=/12/7b+10/7
a=12/7(−2)+10/7
a=−2(Simplify both sides of the equation)
