The slower stone will take 3.33 seconds if the faster stone takes 10s to return to the ground.
It is defined as the rate of change in linear velocity with respect to time. It is also known as linear acceleration.
From the motion equation:
s = ut + at²/2
From the data given:
s = 0
0 = 3u(10) - 9.8(10)²/2
After solving:
u = 16.33 m/s
To calculate for time:
s = ut + at²/2
s = 0
u = 16.33
0 = 16.33t + 9.8t²/2
t = 3.33 seconds
Thus, the slower stone will take 3.33 seconds if the faster stone takes 10s to return to the ground.
The complete question is:
Two stones are thrown vertically upward from the ground, one with three times the initial speed of the other.
(a) If the faster stone takes 10s to return to the ground, how long will it take the slower stone to return?
Learn more about linear acceleration here:
brainly.com/question/408236
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