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A bottle of wine contains 11.0thanol by volume. the density of ethanol () is 0.789 . calculate the concentration of ethanol in wine in terms of mass percent and molality.

Respuesta :

Mass % of ethanol :  8.885

molality of ethanol : 2.12m

Given:

Wine = 11 % ethanol by volume

density of ethanal = 0.789 g/cm3

density of water = 1 g/cm3

let 100 cm3 wine  → 11.0 [tex]cm^3[/tex] ethanol, 89.0 [tex]cm^3[/tex] water.

Mass of ethanol = d x V = 0 789 g/cm3 x 11 cm3 = 8.679 cm3

Mass of water = d x Y = 1.000 g/cm3 x 89 cm3) = 89.00 cm3

Total mass of 100 cm3 wine = 8.679+89 = 97.679 cm3

Mass for % of ethanol = 8: 674 X100 = 8.8857 %

Molar mass of ethanol = 46 g/mole

Moles of ethanol = 8.679/46  = 0.1887 mole

Molality of ethanol = 0.1887/0.089 = 2.12 m

To learn more about mass percent and molality, visit;

https://brainly.com/question/13266022

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