The statement "A 95% confidence interval for the population mean will be wider than a corresponding 99% confidence interval." is true.
It is defined as the sampling distribution following an approximately normal distribution for known standard deviation.
The formula for finding the confidence interval for population standard deviation as follows:
[tex]\rm s\sqrt{\dfrac{n-1}{\chi^2_{\alpha/2, \ n-1}}} < \sigma < s\sqrt{\dfrac{n-1}{\chi^2_{1-\alpha/2, \ n-1}}}[/tex]
Where s is the standard deviation.
n is the sample size.
α is the significance level.
σ is the confidence interval for population standard deviation.
Calculating the confidence interval for population standard deviation:
We know significance level = 1 - confidence level
The statement is:
A 95% confidence interval for the population mean will be wider than a corresponding 99% confidence interval.
As we know,
A 95% confidence interval is narrower than a 99% confidence interval.
Thus, the statement "A 95% confidence interval for the population mean will be wider than a corresponding 99% confidence interval." is true.
Learn more about the confidence interval here:
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