Respuesta :
Mass of CaCl2 = 10 g.
Volume of solution = 1 L.
To determine the solubility, the concentration of CaCl2 solution has to be determined.
The formula for calculating the Molarity (conc. in mol/L) is:
Molarity = Number of Moles of the solute/Volume of solvent in L
The number of moles of solute is determined using the formula:
Number of moles = Mass in g/Molar mass in g/mol = 10g/110.98 g/mol = 0.09 mole.
Now, Molarity = 0.09/1 = 0.09 M
So, the concentration of CaCl2 is 0.09M
CaCl2 dissociates into Ca2+ and 2Cl− ions as shown below.
CaCl2→Ca2+ + 2Cl−
The concentration of Cl− ions in the solution = 2×0.09M =0.18M.
Substitute these values in the expression for the solubility product
Ksp = [Ag+][Cl−] = s×(s+0.18)
Since the value of Ksp is very low, the value of s will be negligible compared to 0.052, and hence,
(s+0.18) ≈0.18
Ksp = s×0.18
1.8×10^−10 =0.052 s
s = 1.8×10^−10/0.18
s = 10 x 10^-10 or 1 x 10^-9M
Therefore, the solubility of AgCl in the given CaCl2 solution is 1x10^-9 M
What is Molar solubility?
The amount of moles of a solute that can dissolve in a solvent before it becomes saturated is known as molar solubility. The amount of solute that dissolves in a liter of solution is most frequently expressed as the number of moles. As a result, it is typically expressed as "M" and measured in moles/liter.
To learn more about Molar solubility refer to:
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