The equation of line which contains points (2,4) and (0,-2) will be y = 3x - 2.
It is given that a line contains points (2,4) and (0,-2).
We have to find out the equation of the line.
What is the equation of line in slope intercept form ?
The equation of line in slope intercept form is y = mx + c , where m is the slope and c is the y-intercept.
As per the question ;
Line contains points (2,4) and (0,-2)
We know that slope intercept form of line is ;
y = mx + c
∴ (2,4) and (0,-2) must satisfy the equation because the line contains them.
So ,
For x = 2 and y = 4 ;
the equation y = mx + c becomes ;
4 = 2m + c ------ ------ ------ ---- (1)
Also ;
For x = 0 and y = -2 ;
the equation y = mx + c becomes ;
-2 = 0 + c
or
c = -2
Put the value of c in equation 1 ;
i.e.,
4 = 2m - 2
2m = 6
or
m = 3
So ,
the equation of line which contains points (2,4) and (0,-2) will be ;
y = (3 × x) - 2
y = 3x -2
Thus , the equation of line which contains points (2,4) and (0,-2) will be y = 3x - 2.
To learn more about slope intercept form of line click here ;
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