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Write an equation of the line containing the points (2,4) and (0,-2) .

Respuesta :

The equation of line which contains points (2,4) and (0,-2) will be y = 3x - 2.

It is given that a line contains points (2,4) and (0,-2).

We have to find out the equation of the line.

What is the equation of line in slope intercept form ?

The equation of line in slope intercept form is y = mx + c , where m is the slope and c is the y-intercept.

As per the question ;

Line contains points (2,4) and (0,-2)

We know that slope intercept form of line is ;

y = mx + c

 (2,4) and (0,-2) must satisfy the equation because the line contains them.

So ,

For x = 2 and y = 4 ;

the equation y = mx + c becomes ;

4 = 2m + c ------ ------ ------ ---- (1)

Also ;

For x = 0 and y = -2 ;

the equation y = mx + c becomes ;

-2 = 0 + c

or

c = -2

Put the value of c in equation 1 ;

i.e.,

4 = 2m - 2

2m = 6

or

m = 3

So ,

the equation of line which contains points (2,4) and (0,-2) will be ;

y = (3 × x) - 2

y = 3x -2

Thus , the equation of line which contains points (2,4) and (0,-2) will be y = 3x - 2.

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