The volume of a potassium atom in microliters is [tex]$4.15 * 10^{-20} \mu L$[/tex]
It is a volume unit conversion problem where we are asked to convert the volume from[tex]$\mathrm{cm}^3$[/tex]to microliters.
We know that:
[tex]$1 \mathrm{~cm}^3=1 \mathrm{~mL}$[/tex]
[tex]$1 m L=10^{-3} L$[/tex]
and, [tex]$1 L=10^6 \mu L$[/tex]
Let's use these conversions factors for the desired conversion using dimensional as:
[tex]$4.15 * 10^{-23} \mathrm{~cm}^3\left(\frac{1 m L}{1 c m^3}\right)\left(\frac{10^{-3} L}{1 m L}\right)\left(\frac{10^6 \mu L}{1 L}\right)$[/tex]
[tex]$=4.15 * 10^{-20} \mu L$[/tex]
So, the answer is [tex]$4.15 * 10^{-20} \mu L$[/tex]
The complete question is,
The volume of a single strontium atom is 4.15×10-23 cm3. What is the volume of a strontium atom in microliters
To learn more about potassium atom refer to:
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