the bacterial cell is 6.25*10 times smaller than the amoeba cell.
To find how many times smaller is the bacterial cell than the amoeba cell, we need to take the quotient between the amoeba cell's length and the bacterial cell's length
We know that:
bacterial cell's length = 4*10^(-6) m
amoebas cell's length. = 2.5*10^(-4) m
The quotient gives:
Q = ( 2.5*10^(-4) m)/(4*10^(-6) m) = (2.5/4)*(10^(-4)*10^6) = 0.625*10^(-4 + 6)
Q = 0.625*10^2
Now we want this in scientific notation, so we need to have a digit in the left fo the decimal point, so we can rewrite this as:
Q = 0.625*10^2 = 6.25*10^1 = 6.25*10
Then the bacterial cell is 6.25*10 times smaller than the amoeba cell.
If you want to learn more about scientific notation:
https://brainly.com/question/5756316
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