The length of a bacterial cell is about 4 x 10−6 m, and the length of an amoeba cell is about 2.5 x 10−4 m. How many times smaller is the bacterial cell than the amoeba cell? Write the final answer in scientific notation with the correct number of significant digits.

6.25 x 102
2 x 102
6 x 101
16 x 101

Respuesta :

the bacterial cell is 6.25*10 times smaller than the amoeba cell.

How many times smaller is the bacterial cell than the amoeba cell?

To find how many times smaller is the bacterial cell than the amoeba cell, we need to take the quotient between the amoeba cell's length and the  bacterial cell's length

We know that:

bacterial cell's length = 4*10^(-6) m

amoebas cell's length. = 2.5*10^(-4) m

The quotient gives:

Q = ( 2.5*10^(-4) m)/(4*10^(-6) m) = (2.5/4)*(10^(-4)*10^6) = 0.625*10^(-4 + 6)

Q = 0.625*10^2

Now we want this in scientific notation, so we need to have a digit in the left fo the decimal point, so we can rewrite this as:

Q = 0.625*10^2 = 6.25*10^1 = 6.25*10

Then the bacterial cell is 6.25*10 times smaller than the amoeba cell.

If you want to learn more about scientific notation:

https://brainly.com/question/5756316

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