Δ A B C has vertices A(-3,3), B(2,5) , and C(4,-3) . What are the coordinates of the centroid of ΔA B C ? Explain the process you used to reach your conclusion.

Respuesta :

The coordinates of the centroid of Δ ABC is y = -1/3x + 2.

What is meant by the slope of the line?

The slope of the line is the rise-to-run ratio or the rise divided by the run. It expresses the slope of a line in the coordinate plane. Finding the slope of a line is similar to determining the slope between two points.

The midpoint D of AC is (-3+4/2, 3-3/2) or (1/2, 0).

Note that DB is a line that connects the vertex B and D, the midpoint of AC.

The slope of the line DB is ((5-0)/(2-1/2)) or 10/3.

The equation of DB is

y - 5 = 10/3 (x - 2)

simplifying the above equation, we get

y - 5 = 10x/3 - 20/3

y - 5 + 5 = 10x/3 - 20/3 + 5

y = 10x/3 - 5/3

Use the same method to find the equation of the line between point A and the midpoint of BC.

Therefore, the coordinates of the centroid of Δ ABC is y = -1/3x + 2.

To learn more about the slope of the line refer to:

https://brainly.com/question/16949303

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