If AB = 6y - 14, BC = 10 - 2y then the value of AC = 8.
In geometry, the midpoint is the point in the middle of a line segment. It is equidistant from both endpoints and serves as the segment and endpoint centroid. It cuts the segment in half.
Given: AB = 6y - 14, BC = 10 - 2y
Since B is the midpoint of AC, AB = BC then
6y - 14 = 10 - 2y
Add 14 on both sides of the equation, and we get
6y - 14 + 14 = 10 - 2y + 14
6y = - 2y + 24
Add 2y on both sides of the equation
6y + 2y = - 2y + 24 + 2y
simplifying the above equation, we get
8y = 24
y = 24/8
y = 3
Substitute the value of y in AC then we get
AC = 2(6(3) - 14)
= 2(4)
AC = 8
Therefore, the value of AC = 8.
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