The intake to a hydraulic turbine (not drawn to scale) installed in a dam is located at an elevation of 10 meters above the turbine exit. Water enters at
20℃ with negligible velocity and exits from the turbine at 10m/s. The water passes through the turbine with no significant changes in temperature or pressure between the inlet and exit, and heat transfer is negligible. The acceleration of gravity is constant at g = 9.81 m/s2. If the power output at a steady state is 500 kW, what is the mass flow rate of water in kg/s?

Respuesta :

The mass flow rate of water is 5.146×10³ kg/s

The enthalpy change that occurs during a reaction is the heat that enters or exits the system. A critical factor that determines whether a reaction may occur is whether the enthalpy of the system increases (i.e., because energy is added) or lowers (i.e., because energy is given off).

Elevational difference (Z1-Z2) =15m

V1 = the inlet velocity, V2 = the outlet velocity

Using the equation for steady-state energy Q+m(h1+V2/12+g/z1) =W+m(h2+V22/2+gz2),

m(h1+V21/2+g/z1) m(h2+V22/2+g/z2) =WQ, and m(h1h2+V2/12V22/2+g/z1g/z2) =WQ.

The change in enthalpy and the rate of heat transfer are both zero because the pressure and temperature have barely changed.

m (0−0+0/22−10/22+9.81× (15))

=500×1000m\s

=5.146×10³ kg/s

Learn more about Enthalpy here-

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