[tex]Answer:\ f^{-1}(x)=\sqrt[3]{x} -4[/tex]
Step-by-step explanation:
[tex]f(x)=(x+4)^3[/tex]
Extract the cube root from both parts of the equations:
[tex]\sqrt[3]{f(x)} =x+4\\\sqrt[3]{f(x)}-4=x+4-4\\ \sqrt[3]{f(x)} -4=x[/tex]
Redefine the variables:
[tex]f^{-1}(x)=\sqrt[3]{x} -4[/tex]
