Respuesta :
The compound's empirical formula is CH3O.
Empirical formula is the chemical formula for compounds which do not define the precise number or arrangement of atoms but just the quantities of the components they contain. This would be the component of the compound with the smallest whole number ratio.
Empirical formula is beneficial since figuring out the molecular formula may be immensely aided by knowing the relative amounts of each constituent in a molecule. It's crucial to have an n-value in order to figure out the real number of each atom in a molecule.
n(CO2) = n(C) = m/M = 6.557/44 = 0.148 mol
m(C) = 0.148 x 12 = 1.788g
n(H2O) = 0.5n(H) = 5/22.4 = 0.223g/18 = 0.024 mol
m(H) = 2 x 0.024 = 0.048g
m(O) = 4.624 - 1.788 - 0.048 = 2.788g
n(H) = 2 x 0.174 = 0.348 mol
n(O) = 2.788/16 = 0.174 mol
n(C):n(H):n(O) = 0.148:0.348:0.174 = 1:3:1
Empirical formula is CH3O
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