Answer:
Correct option is B) Consider a Gaussian surface (cylinder in this case) of radius r and length l. Then according to the Gauss's Law of electrostatics:∫E.dA=ϵ0qenclosedFrom the symmetry of the surface, we can easily say that the electric field would only be along the radial direction. And the amount of charge enclosed by this cylinder is qenclosed=λ×l and the surface area of the cylinder A=2πrl. So, E×2πrl=ϵ0λl E=(2πϵ01)rλ
Explanation:
