Surds please answer this question

Answer:
Step-by-step explanation:
[tex]\displaystyle\\\frac{1}{1+\frac{1}{\sqrt{3} } }=\\\\\frac{1}{\frac{1*\sqrt{3} +1}{\sqrt{3} } } =\\\\\frac{1*\sqrt{3} }{\sqrt{3}+1 }=\\\\\frac{(\sqrt{3})(\sqrt{3}-1) }{(\sqrt{3}+1)(\sqrt{3}-1) }=\\\\\frac{(\sqrt{3})(\sqrt{3})-(1)(\sqrt{3}) }{(\sqrt{3})^2-1^2 } =\\\\\frac{3-\sqrt{3} }{3-1} =\\\\\frac{3-\sqrt{3} }{2}[/tex]