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In the diagram, BC ∥ DE
What is CE ?
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The length of CE is 15 m
From the question,
We are to determine the length of CE
In the diagram, ΔADE and ΔABC are similar triangles
By similar triangle theorem, we have that
[tex]\frac{AD}{BD}=\frac{AE}{CE}[/tex]
From the diagram,
AD = 2 m
BD = 10 m
AE = 3 m
Putting the values into the equation
[tex]\frac{AD}{BD}=\frac{AE}{CE}[/tex]
We get
[tex]\frac{2}{10}=\frac{3}{CE}[/tex]
Then, we can write that
[tex]2 \times CE = 3 \times 10[/tex]
∴ [tex]CE = \frac{3 \times 10}{2}[/tex]
[tex]CE =\frac{30}{2}[/tex]
∴ CE = 15 m
Hence, the length of CE is 15 m
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