Triangle ABC is similar to triangle DEF. The length of BC is 21cm. The length of DE is 10 cm. The length of EF is 14 cm. What is the length of AB?

Respuesta :

It's a similar triangle so the ratios of corresponding sides should be equal which means

BC/EF = AB/DE
21/14 = AB/10
AB = 21/14 * 10 = 15 cm

The required length of AB = 21cm.

Given that,

Triangle ABC is similar to triangle DEF.

The length of BC is 21cm,

The length of DE is 10 cm,

The length of EF is 14 cm.

We have to find ,

The length of AB.

According to the question,

Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion.

Then, It's a similar triangle so the ratios of corresponding sides should be equal which means.

Now,

[tex]\frac{BC}{EF} = \frac{AB}{DE} \\\\\frac{21}{14} = \frac{AB}{10} \\\\AB = \frac{(21).(10)}{14}[/tex]

AB = 15cm

Hence, The required length of AB = 21cm.

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