Two consecutive numbers whose sum is 115 are : 57 and 58
Let the first number be x & the second number be y
So, Equations can be formed as follows :
y-x = 1 ............(Eq . 1)
x+y = 115..........(Eq . 2)
Using Eq. 1,
y = x+1 ...............(Eq . 3)
Using Eq . 3 in Eq . 2 ,
x + ( x + 1 ) = 115
2 x + 1 = 115
2 x = 115 - 1
2 x = 114
x = 114/2
x = 57
Now, using x = 57 in Eq. 3 ,
y = x + 1
y = 57 + 1
y = 58
Hence, the required consecutive numbers are 57 and 58
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