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A boy throws a ball straight up into the air. It reaches the highest point of its flight after 4 seconds-How fast was the ball going when it left the boy's hand?

Respuesta :

agarwallachirag1

Answer:

Answer is

[tex]4g \: m {s}^{ - 1} [/tex]

Explanation:

We have to find the initial velocity, u.

Final velocity is v = 0. And acceleration is due to gravity.

Now,

[tex]v = u + at[/tex]

[tex]0 = u + ( - g)m {s}^{ - 2} \times 4s[/tex]

[tex]u = 4g \: m {s}^{ - 1} [/tex]

Therefore, the final answer depends on the value of g.

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