(-1,6) is point 3,-2 reflected over y=-4 in equation .
What is the reflection guideline?
y = 4 is a horizontal line. 4-2 = 2, and y= 4 is above our point, so A' is (-3,6).
|-3 -(-2)| = 1, so moving it 1 to the other side of x = -2 gives us...
(-1,6)
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