Answer:
[tex]d=1/2[/tex]
How to solve:
Step-by-step explanation:
[tex]\frac{5}{6}=\frac{1}{3}+d\\\frac{1}{3}+d=\frac{5}{6}[/tex]
Group
[tex]\frac{1}{3}+d=\frac{5}{6}\\\frac{1}{3}+d-\frac{1}{3}=\frac{5}{6}-\frac{1}{3}\\d+\frac{1}{3}+\frac{-1}{3}=\frac{5}{6}-\frac{1}{3}\\d+\frac{1-1}{3}=\frac{5}{6}-\frac{1}{3}\\d+\frac{0}{3}=\frac{5}{6}-\frac{1}{3}\\d+0=\frac{5}{6}-\frac{1}{3}\\d=\frac{5}{6}-\frac{1}{3}\\d=\frac{5}{6}+\frac{-1\cdot 2}{3\cdot 2}\\d=\frac{5}{6}+\frac{-1\cdot 2}{6}\\d=\frac{5}{6}+\frac{-2}{6}\\d=\frac{5-2}{6}\\d=\frac{3}{6}\\d=\frac{1\cdot 3}{2\cdot 3}\\d=\frac{1}{2}[/tex]
Hope it helps.
