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Answer:
-12y^10
Step-by-step explanation:
First let's rewrite the equation using the commutative property of multiplication
3 x (-4)y^8y^2
Multiply y^8 by y^2 by adding the exponents
y^8+y^2= y^10
3 x (-4)y^10
Now multiply 3 by -4
3 x -4= -12
Finally put them together
-12 + y^10= -12y^10
Answer:
[tex] - 12 {y}^{10} [/tex]
Step-by-step explanation:
We are to simplify:
[tex](3 {y}^{8} )( - 4 {y}^{2} )[/tex]
3 multiplies -4 to get -12, as shown below
[tex]3 \times - 4 = - 12[/tex]
Now, to multiply the exponents which are 8 and 2, we have to use the exponential rule of multiplication: [tex] {a}^{b} \times {a}^{c} = {a}^{b + c} [/tex]
Therefore:
[tex] {y}^{8} \times {y}^{2} = = > {y}^{8 + 2} = {y}^{10} [/tex]
Now, combine -12 and [tex] {y}^{10} [/tex] to get your final answer.
Final answer [tex] = - 12 {y}^{10} [/tex]