Respuesta :
Answer: The work done by the boat is [tex]2\times 10^8 Joules[/tex].
The power of the wind is [tex]5.55\times 10^4 watts[/tex].
Explanation:
Force of the wind in the boat = [tex]2.00\times 10^4 N[/tex]
Displacement of the boat = 10 km = 10,000 m
Work done = Force × Displacement =
[tex]2\times 10^4 N\times 10,000 m=2\times 10^8 Joules[/tex]
Duration of time for which boat sailed = 1 hour
Power of the wind = [tex]\frac{Energy}{Time}[/tex]
=[tex]\frac{2\times 10^8 Joules}{1\times 60\times 60 seconds}=5.55\times 10^4 watts[/tex]
The work done by the boat is [tex]2\times 10^8 Joules[/tex].
The power of the wind is [tex]5.55\times 10^4 watts[/tex].

Answer:
Work done = 1.414 × 10⁸ J
Power of the wind = 3.9 × 10⁴ W
Explanation:
Work done by the wind is scalar product of force and displacement of the sailboat.
W = F.s = F s cos θ
Here, sailboat is moving Northwards when Wind from South-East strikes it. Thus, the angle between force and displacement is θ =45°
F = 2.00×10⁴ N
s = 10.00 km = 10⁴ m
W = 2.00×10⁴ N × 10⁴ m × cos 45° = 1.414 × 10⁸ J
Power of the boat = work done per unit time
time = 1 h = 3600 s
[tex]P = \frac{1.414 \times 10^8 J}{3600 s} = 3.9 \times 10^4 W[/tex]
