Respuesta :
Answer: 0.9J/g°C.
Explanation:
Specific heat of Aluminum is the amount of heat required to raise one gram of Aluminum by one degree Celsius.
The formular is Q=mc∆T
Where Q is energy in joules.
M is mass in gram.
C is specific heat.
∆T is change in temeprature in degree Celsius.
Mass=28.4g
C=?
T=8.1°c
Q=207j.
Q=MC∆T
207= 28.4× C× 8.1
207=230.04C
C=207÷230.04
C=0.9J/g°C.
The specific heat of aluminum is 0.9 J/g°C.
What is specific heat?
The specific heat capacity of any substance is the heat capacity divided by the mass of the substance.
By the formula
Q=mc∆T
Q is the energy which is 207 J
m is mass, which is 28.4 g
T is temperature which is 8.1 C
delta is change in temperature
Putting the values in the formula
Q=mc∆T
207 = 28.4 × c × 8.1
c = 0.9 g/J
Thus, the specific heat capacity of aluminum is 0.9 g/J
Learn more about specific heat
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