Answer:
[tex]2.72\cdot 10^{-4} kg/m[/tex]
Explanation:
The terminal speed is reached by an object in free fall when the force of gravity becomes equal to the air resistance:
[tex]W=R[/tex]
This can be rewritten as
[tex]mg=bv^2[/tex]
where
m is the mass of the object
g is the gravitational acceleration
b is the coefficient of the air resistance
v is the speed of the object
In this problem, we have m = 2.3 g = 0.0023 kg, g=9.8 m/s^2 and v=9.1 m/s. Substituting and re-arranging the equation we find
[tex]b=\frac{mg}{v^2}=\frac{(0.0023 kg)(9.8 m/s^2)}{(9.1 m/s)^2}=2.72\cdot 10^{-4} kg/m[/tex]
