If f(x)=2(x)^2 + 5 square root (x-2), complete the following statement
The domain for f(x) is all real numbers _____ than or equal to 2.

The in the function , the square root term has to give a real number if is to be real. This can only happen if because if then will give a complex number and therefore will not be real.

Thus, the domain for f(x) is all real numbers greater than or equal to 2.

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semsee45 semsee45 · Answer 2 · 2022-10-09T23:27:14+02:00

Answer:

The domain for f(x) is all real numbers greater than or equal to 2.

Step-by-step explanation:

Given function:

[tex]f(x)=2x^2+5 \sqrt{x-2}[/tex]

The domain of a function is the set of all possible input values (x-values).

As the square root of a negative number cannot be taken:

[tex]\implies x-2\geq 0[/tex]

Therefore:

[tex]\implies x-2+2\geq 0+2[/tex]

[tex]\implies x\geq 2[/tex]

Therefore, the domain of the given function is greater than or equal to 2.

If f(x)=2(x)^2 + 5 square root (x-2), complete the following statement The domain for f(x) is all real numbers _____ than or equal to 2.

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If f(x)=2(x)^2 + 5 square root (x-2), complete the following statement
The domain for f(x) is all real numbers _____ than or equal to 2.