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Suppose 87.1 mL of a 0.190 M solution of Na2SO4 reacts with 143 mL of a 0.311 M solution of MgCl2 to produce MgSO4 and NaCl as shown in the balanced reaction

Na2SO4(aq)+MgCl2(aq)⟶MgSO4(s)+2NaCl(aq)

1. Calculate the mass of MgSO4 that can be produced in the given reaction.

2. Only 0.212 g of MgSO4 are isolated after carrying out the reaction. Calculate the percent yield of MgSO4

Respuesta :

Hunter120H

Answer:

Magnesium Chloride + Sodium Sulfate = Magnesium Sulfate + Sodium Chloride

1 mole of aqueous Magnesium Chloride [MgCl2] reacts with 1 mole of aqueous Sodium Sulfate [Na2SO4] to form 1 mole of aqueous Magnesium Sulfate [MgSO4] and 2 moles of aqueous Sodium Chloride [NaCl]

Mg²⁺

Cl⁻

Cl⁻

O⁻

S

O

O

O⁻

Na⁺

Na⁺

O⁻

S

O

O

O⁻

Mg²⁺

Na⁺

Cl⁻

Explanation:

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