Respuesta :
A. The searchers should cover the greatest area which can be calculated by assuming that the distance covered by the bear for 4 hours is the radius of the circle.
radius = (2 miles/hour)(4 hours) = 8 miles
area = 2(3.14)(8 miles)² = 401.92 mi²
B. I would assume that for this number, we are to solve the additional area to be covered if the bear was last seen 5 HOURS ago.
radius = (2 miles/hour)(5 hours) = 10 miles
area = (2)(3.14)(10 miles)² = 628 mi²
We get the answer for B by subtracting the two areas which will give us an answer of 226.08 mi².
radius = (2 miles/hour)(4 hours) = 8 miles
area = 2(3.14)(8 miles)² = 401.92 mi²
B. I would assume that for this number, we are to solve the additional area to be covered if the bear was last seen 5 HOURS ago.
radius = (2 miles/hour)(5 hours) = 10 miles
area = (2)(3.14)(10 miles)² = 628 mi²
We get the answer for B by subtracting the two areas which will give us an answer of 226.08 mi².
Answer:
Step-by-step explanation:
Given data:
Rate of walk of bear is 2 miles per hour
Bear was seen 4 hr before
The bear can walk 8 miles (2× 4) since it is walking 2 miles/hr for 4 hr, therefore radius of then 8
Use areas of circle to calculate the area cover by searcher
[tex]A = \pi r^2[/tex]
[tex]A = \pi (8)^2 = 201[/tex]
b) when bear seen 5 hr ago thus
The bear can walk 8 miles (2× 5) since it is walking 2 miles/hr for 4 hr, therefore radius of then 10
Use areas of circle to calculate the area cover by searcher
[tex]A = \pi r^2[/tex]
[tex]A = \pi (10)^2 = 314[/tex]
Additional area = 314 - 201 = 113