A cone has a radius of 5 inches and a height of 5 inches.

What is the volume of the cone to the nearest tenth in³?

Use 3.14 to approximate pi.

25.0 in³

75.0 in³

125.4 in³

130.8 in³

Respuesta :

volume of a cone = πr²(h/3)
π=3.14
r=5
h=5

v = (3.14)(5)²(5/3)
v = (3.14)(25)(5/3)
v ≈ 130.8 in³

the last choice is your answer, 130.8 in³

Answer:

Option 4th is correct

130.8 in³

Step-by-step explanation:

Volume of a cone (V) is given by:

[tex]V = \frac{1}{3} \pi r^2h[/tex]              .....[1]

where,

r is the radius of the cone

h is the height of the cone.

As per the statement:

A cone has a radius of 5 inches and a height of 5 inches

⇒r = 5 inches and h = 5 inches

Use [tex]\pi = 3.14[/tex]

Substitute these in [1] we have;

[tex]V = \frac{1}{3} \cdot 3.14 \cdot 5^2 \cdot 5[/tex]

⇒[tex]V= \frac{1}{3} \cdot 3.14 \cdot 125[/tex]

Simplify:

[tex]V = 130.833334[/tex] in³

Therefore, the volume of the cone to the nearest tenth is, 130.8 in³