Respuesta :

apologiabiology
P=2(L+W)
when we double each
Pnew=2(2L+2W)
Pnew=2(2(L+W))
Pnew=2(P)
the perimiter is doubled

if you wanted the actual perimiter
P=2(L+W)
P=2(12.5+105)
P=2(117.5)
P=235 m
double it to get
470m is the doubled perimiter
carlosego

For this case we have that by definition, the perimeter of a rectangle is given by:

[tex]P = 2 (w + l)[/tex]

Where,

  • w: width of the rectangle
  • l: length of the rectangle

The original perimeter is given by:

[tex]P1 = 2 (12.5 + 105)\\P1 = 235[/tex]

Then, the new perimeter is given by:

[tex]P2 = 2 ((2 * 12.5) + (2 * 105))\\P2 = 2 * 2 (12.5 + 105)\\P2 = 2 * 235\\P2 = 2 * P1[/tex]

Therefore, the original perimeter increases by a factor of 2.

Answer:

the original perimeter increases by a factor of 2.

[tex]P2 = 2 * P1[/tex]


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