The equation y=10(1.0605)^x represents the winning prize money, in thousands, for first place in the Indianapolis 500 auto race. Let x represent the number of years. Let x=0 for the year of the race in 1911. Find the winning prize money in 1961? (Hint: Let x = 50 for 1961)

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Answer:

$189,000

Step-by-step explanation:

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To find out the prize money the equation given in the question can be used.

Winning prize money in 1961 is $188.59.

Let [tex]\rm \bold y[/tex] represent the prize money and x represent the number for year.

From the question the winning prize money equation can be given by the equation (1) which is formulated below,

[tex]\rm y = 10 \times (1.0605)^x....... (1)[/tex]

y = Price money as multiple of thousand dollars.

x = Number of years.

For 1961 the prize money can be given found out by putting in the equation (1) . From the the given hint we can write that  x = 50 for year 1961. So from equation  (1) we can write that

[tex]\rm y = 10\times (1.0605)^{50}\\y =10\times 18.8596\\\rm y = 188.59 $[/tex]

So the winning prize money in 1961 is $188.59.

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https://brainly.com/question/20821733