Respuesta :
that is the x value of the vetex
in form
y=a(x-h)^2+b
vertex is (h,k)
so look for h
y=2(x+3)^2+5
y=2(x-(-3))^2+5
x value is -3
x=-3 is axis of symmetry
in form
y=a(x-h)^2+b
vertex is (h,k)
so look for h
y=2(x+3)^2+5
y=2(x-(-3))^2+5
x value is -3
x=-3 is axis of symmetry