Respuesta :
The function H(t) = -16t^2 + 64t is a parabola.
The axis of symmetry of a parabola is at the midpoint between the two real roots.
The roots are the solutions of H(t) = 0
Then find the roots:
-16t^2 + 64t = 0
Factor => t(-16t + 64) = 0 => t = 0 and -16t + 64 =0
-16t + 64 = 0 => t = 64 / 16 = 4
Then the two roots are t = 0 and t = 4, and the axis of symmetry is t = (0 + 4) / 2 = 4/2 = 2
Answer:
The axis of simmetry is t = 2.
It represents the time at which the ball is at the higher point, i.e the maximum height.
You can find the maximum height replacing t = 2 in the function H(t)
H(t) = -16(2^2) + 64(2) = 64 feet.
And you can also deduce that the second part of the flight will take 2 seconds, for a total flight time of 4 seconds.
The axis of symmetry of a parabola is at the midpoint between the two real roots.
The roots are the solutions of H(t) = 0
Then find the roots:
-16t^2 + 64t = 0
Factor => t(-16t + 64) = 0 => t = 0 and -16t + 64 =0
-16t + 64 = 0 => t = 64 / 16 = 4
Then the two roots are t = 0 and t = 4, and the axis of symmetry is t = (0 + 4) / 2 = 4/2 = 2
Answer:
The axis of simmetry is t = 2.
It represents the time at which the ball is at the higher point, i.e the maximum height.
You can find the maximum height replacing t = 2 in the function H(t)
H(t) = -16(2^2) + 64(2) = 64 feet.
And you can also deduce that the second part of the flight will take 2 seconds, for a total flight time of 4 seconds.
The axis of the symmetry of a parabola is a vertical line that divides the parabola in two equal parts. The axis of the symmetry is 2 which represents that the maximum height (64 units) reached by the ball is after two seconds.
Given information-
The height of the ball is modeled with the function,
[tex]H(t)=-16t^2+64t[/tex]
Here t is the time in seconds.
Axis of symmetry
The axis of the symmetry of a parabola is a vertical line that divides the parabola in two equal parts.
As the roots of the parabola divides it into the two equal part. Therefore equate the equation to the 0 for finding the roots of the equation.
[tex]-16t^2+64t=0\\ -16t(t-4)=0[/tex]
Thus one roots of the equation are,
[tex]\begin{aligned}\\ -16t&=0\\ t&=0\\ \end[/tex]
Another root,
[tex]\begin{aligned}\\ t-4&=0\\ t&=4\\ \end[/tex]
The roots of the equation are (0,4). The axis of the parabola is the half of the sum of the roots of the equation of that parabola,
[tex]t=\dfrac{0+4}{2} \\ t=2[/tex]
Put this value of t in the given equation to find the height.
[tex]H(t)=-16\times2^2+64\times2\\ H(t)=-64+128\\ H(t)=64[/tex]
Hence the axis of the symmetry is 2 which represents that the maximum height (64 units) reached by the ball is after two seconds.
Learn more about the axis of symmetry here;
https://brainly.com/question/21589886