Answer:
the altitude of the plane to the nearest foot is, 277 feet high
Step-by-step explanation:
Using tangent ratio:
[tex]\tan \theta = \frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]
As per the statement:
The glide slope usually makes a 3º angle with the ground.
⇒[tex]\theta = 3^{\circ}[/tex]
A plane is on the glide slope and is 1 mile (5280 feet) from touchdown.
⇒Adjacent side= DF = 1 mi = 5280 feet.
We have to find the EF.
Using tangent ratio:
[tex]\tan \theta^{\circ}= \frac{\text{EF}}{\text{DF}}[/tex]
Substitute the given values we have;
[tex]\tan 3^{\circ}= \frac{\text{EF}}{5280}[/tex]
Multiply both sides by 5280 we have;
[tex]\text{EF} = 5280 \cdot \tan 3^{\circ}[/tex]
⇒[tex]\text{EF} = 5280 \cdot 0.05240777928[/tex]
Simplify:
EF = 276.713074614 feet.
Therefore, the altitude of the plane to the nearest foot is, 277 feet high
