The root mean square speed of O₂ gas molecules under the same conditions is 521.04ms⁻²
Kinetic energy is the energy an object has because of its motion
Here given data is
He gas = 6950 j/mol
We have to find root mean square = ?
So the formula is to find root mean square is
Vrms = √RT/m
Vrms = RMS velocity of the gas
T = absolute temprature of the gas
M = molar mass of the gas
R = universal gas constant
So, average molar kinetic energy of gas
E = 1/2 mv²rms = 1/2 RT
This equation reveal that molar KE is independent of the nature of the gas and it only depends on temprature as ideal behavior is concerned and so both He and O₂ will have same KE = 6950 j/mol and under the same condition of temprature
So for O₂
1/2 m O₂ V²rmsO₂ = 6950 j/mol
Taking atomic mass of O₂ = 16g/mol
V²rmsO₂ = 6950 × 2/2×16g/mol
VrmsO₂ = √69500000/16g/mol
VrmsO₂ = 521.04ms⁻²
Root mean square speed of O₂ gas molecules is 521.04ms⁻²
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