. in an analysis of interhalogen reactivity, 0.500 mol of icl was placed in a 2.00 - l flask, where it decomposed at a high t: 2 icl(g) i 2 (g) cl 2 (g) calculate the equilibrium concentration of icl (k c

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08-11-2022
Chemistry

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. in an analysis of interhalogen reactivity, 0.500 mol of icl was placed in a 2.00 - l flask, where it decomposed at a high t: 2 icl(g) i 2 (g) cl 2 (g) calculate the equilibrium concentration of icl (k c

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AnnuG AnnuG · Answer 1 · 2022-11-11T11:15:54+01:00

The equilibrium concentration of ICl is 17.97M

Equilibrium concentration is when both reactant and product are in concentration which does not change with time any more

Here given data is

Volume = 2.00L

Number of moles of ICl = 0.440 moles

Kc = 0.110

Balanced chemical equation

2ICl ⇄ I₂ + Cl₂

We have to calculate equilibrium concentration of icl = ?

Calculations for initial concentration

ICl = 0.440 moles/ 2.00L = 0.22M

I₂ = 0M

Cl₂ = 0M

Concentration of equilibrium

ICl = (0.22M - 2x)M

I₂ = xM

Cl₂ = xM

Calculation for Kc

Kc = 0.110 = [I₂][Cl₂]/[ICl]

0.110 = x²/ (0.22M-2x)²

0.332 = x(0.22M-2x)

x = 0.332×(0.22M-2x)

x = 0.0730 - 0.664x

0.664x = 0.0730

x = 0.664/0.0730

x = 9.095

The equilibrium concentration will

[I₂] = [Cl₂] = 9.095M

[ICl] = 0.22M - 2(9.095)

[ICl] = 17.97M

Equilibrium concentration of ICl is 17.97M

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