The probability of having at least one dog adopted is 0.6126
It is given that the probability to adopt a dog is 0.1
The adoption of the dog here clearly follows a Binomial distribution
ⁿCₓ X pˣ X (1 - p)ⁿ⁻ˣ
where,
n = no. os sample
p = probability of success
x = random variable.
Here the success would be the adoption of a dog, We are given here there were 9 visits
Hence,
n = 9
p = 0.1
1 - p = 0.9
we need to find the probability of the adoption of at least one dog
= P(X ≥ 1)
= 1 - P(X = 0)
Hence we get
P(X = 0)
= ⁹C₀ X 0.1⁰ X 0.9⁹
= 0.3874
Hence,
P(X ≥ 1)
= 1 - 0.3874
= 0.6126
Therefore the probability that at least one dog will be adopted is 0.6126
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