The probability of having at least one employee not have a college degree is 0.595
Here it is given that the 74% of employees have a college degree.
Hence, the probability of one employee having a college degree is
74/100
= 0.74
The probability that an employee does not have a college degree is
1 - 0.74
= 0.26
Hence
The above problem is clearly a Binomial distribution. with n = 120 and p = 0.26
"success" is when one employee does not have a college degree.
Therefore the probability that at least 1 employee does not have a college degree is
P(X≥1)
= 1 - P(X = 0)
A binomial distribution with sample n and probability p has a PMF
ⁿCₓ X pˣ X (1 - p)ⁿ⁻ˣ
where x is a random variable
Here
n = 3
p = 0.28
x = 0
Hence we get
³C₀ X 0.26⁰ X (0.74)³
0.405
Therefore,
P(X≥1)
= 1 - 0.405
= 0.595
To learn more about Probability visit
https://brainly.com/question/28168108
#SPJ4
