The concentration of H₃PO₄ that is needed to neutralize 17.61 ml of 2.869 m NaOH when 31.16 ml of H₃PO₄ is used is 0.540 M.
The balanced equation is given as :
H₃PO₄ + 3NaOH ------> Na₃PO₄ + 3H₂O
number of moles of NaOH = 0.0176 × 2.869
= 0.050 mol
moles of moles of H₃PO₄ needed = 0.050 / 3 =0.0168 mol
molarity of H₃PO₄ = moles / volume in L
= 0.0168 / 0.0311
= 0.540 M
Thus, The concentration of H₃PO₄ that is needed to neutralize 17.61 ml of 2.869 m NaOH when 31.16 ml of H₃PO₄ is used is 0.540 M.
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