Respuesta :
The continuous annual decay rate of carbon-14 is k = ln (0.5)/5730.
The 1/2-life of a radioactive isotope is the quantity of time it takes for one-1/2 of the radioactive isotope to decay. The half of-existence of a selected radioactive isotope is consistent; it's miles unaffected by using situations and is independent of the initial quantity of that isotope.
1/2-life (symbol t1⁄2) is the time required for an amount (of substance) to reduce to half of its initial price. The time period is commonly utilized in nuclear physics to explain how speedy volatile atoms undergo radioactive decay or how long strong atoms survive.
Calculation:-
The functions as an exponential decay function as
P(t)=P₀e^{kt}
given the half-life as 5730 years, that is the time taken to reduce the mass to half
P₀/2 =P₀e^{5730k}
1/2=e^{5730k}
taking the natural log,
5730k=ln (0.5)
we get the exact continuous decay rate as
k = ln (0.5)/5730
Learn more about radioactive substances here:-https://brainly.com/question/25750315
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