The final velocity (in m/s) of a hoop that rolls without slipping down a 5.00-m-high hill, starting from rest will be 31.30 m/s
given
initial velocity = 0
displacement = s = 50 m
using kinematics equation
2as = [tex]v^{2} - u^{2}[/tex]
2* (g) * s = [tex]v^{2}[/tex] - 0
[tex]v^{2}[/tex] = 2 * (9.8) * 50
v = 31.30 m/s
The final velocity will be v = 31.30 m/s
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