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two cars, car x and car y, are moving with the same velocity, and slam on the brakes coming to a stop. car x is more massive than car y. for which car is the amount of work done by friction in stopping it the highest?

Respuesta :

The amount of work done by friction in stopping the car is given as

Wx > Wy.

There are two cars moving with the same velocity

car X is more massive than car Y

mass of car X = Mx

mass of car Y = My

here given,  Mx >  My

The distance travelled will be the same as the initial velocity, and it is independent of mass.

Let, μ be the coefficient of kinetic friction

work done by the frictional force is given as:

F = μMg

Fx = μMxg

Fy = μMyg

W = F.s

Wx = μMxg.s

Wy = μMyg.s

Wx > Wy

The amount of work done by friction in stopping the car is given as

Wx > Wy.  

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